Question

three blocks of masses M1 equals to 1 kg M2 equals to 1.5 kg and 3 equals to 2 kg in contact with each other on a frictionless surface as shown in figure find the horizontal force f needed to push the blocks as a single you need with an acceleration of 4 metre second square resultant force on each block and magnitude of contact forces between blocks​

Answer 1

Answer:

Explanation:

let blocks of masses m1 = 3kg, m2 = 2 kg and m3 = 5 kg areplaced on inclined plane as shown in figure.

if F is the force required to push the blocks up with acceleration 2 m/s2 , then we have, F - (10×10×sin30) = F - 50 = 10×2

Hence F = 70 N

Contact force between m1 and m2 = 3×cos30 ≈ 2.6 N

Contact force between m2 and m3 = 5×cos30 ≈ 4.3 N

Answer 2

$Given$

$m1= 1 kg$

$m2= 1.5 kg$

$m3= 2 kg$

$acceleration = 4m/s^2$

Total horizontal force =

F = m1+m2+m3

= 1+1.5+2

=4.5 N

resultant force on each block =

F1 = m1×a

= 1×4=4 N

F2=m2×a

= 1.5×4=6 N

F3= m3 × a

= 2×4=8 N