Question

three blocks of masses m1 ,m2 ,m3 are connected by massless strings as shown on a friction less table they are pulled witha force T3 =40N ,if m1=10kg,m2=6kg,m3=4kg then t2= ? i will mark u as brainliest*

Answer 1

total mass of system = 20 kg

acceleration of system = F/m = 40 N/20 kg = 2.0 m/s2

t3<------3---<----2-----1

string t2 pulls blocks 2 and 1, so

the tension in the string t2 = (m1 +m2) a = 32 N

Answer 2

Given that,

Mass of first block $m_{1}=10\ kg$

Mass of second block $m_{2}=6\ kg$

Mass of third block $m_{3}=4\ kg$

Total force = 40 N

We need to calculate the acceleration

Using formula of force

$F=ma$

$a=\dfrac{F}{m}$

Put the value into the formula

$a=\dfrac{40}{10+6+4}$

$a=\dfrac{40}{20}$

$a=2\ m/s^2$

t₂ is applied on first and second block

We need to calculate the tension t₂

Using formula for tension t₂

$F=ma$

Put the value into the formula

$F=(10+6)\times2$

$F=32\ N$

Hence, The tension t₂ will be 32 N.