Question

three blocks placed one after the other are pushed by a force F as shown in fig. Determine the contact force exerted by m2 on m3?

Answer 1

hope this helps you.....

Answer 2

The total mass of the three blocks given in the figure = (m₁ +m₂ + m₃) Kg

The acceleration of the blocks = $\frac{external\ force}{Total\ mas \ of\ the\ blocks}$

The external force acting on the blocks = F N

Acceleration = $\frac{F }{m_{1}+m_{2} +m_{3}}$

The force between the block m₂ and m₃ is action-reaction pair.

Let the force act by the m₂ on m₃ be F₂₃.

Hence, the force exerted by m₃ on m₂ will be F₃₂.

F₂₃ = - F₃₂

F₂₃ can be calculated as = $mass\times acceleration$

The force (F₂₃) = $m_{3}\times \frac{F }{m_{1}+m_{2} +m_{3}}$