Question

Three boats are in the sea: A1, A2, and A3. The crew on A1 con see both A2 and A3. Th a angle between the line of sight of A2 and line of sight of A3 is 45°. If the distance between A1 and A2 is 2 miles and the distance between A1 and A3 is 4 miles.
1.Make a draw of the triangle that represents the situation.
2. what is the distance between A2 and A3?

Answer 1

Answer:

a(base1)+a(base2)+a(base3)+ a(base4) + ………..+ a(base n) = 3*(2^(n+1) -2)

Put n =1

a(base1) = 3*(2^2 -2) = 6

Put n =2

a(base1)+a(base2) = 3*(2^3 -2) = 18

Or a(base2) = 12

Put n =3

a(base1)+a(base2)+a(base3) = 3*(2^4 -2) = 42

a(base3) = 42 – a(base2) – a(base1) = 42 – 12 – 6 =24

we can see that a1, a2 , a3 form a GP with common ratio 2 so

a(base11) = a(base1)*2^10 = 6*1024 = 6144