Question

Three bodies A(1kg),B(2kg)andC(3kg)are connected by light inextensible strings and the system is pulled with a force F .If the tension in the string connecting B and C is 4.5N, the force F is

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Answer 1

Answer:

9 N

let the force be  F

tension between B & C block is 4.5 N

let a be the acc produced by the force

then F=6*a

now balancing the block C force  a forward force F is acting on it a backward tension is acting on it and block is also having a acc

so

3*a = F -tension   -(1)

now total force on block a & b is 4.5 N

this force is responsible for their motion and acceleration

so

4.5 =(1+2)*a

a = 1.5 m/s^2

now putting values of a and tension in eqn 1

F= 9 N