Question

Three bombs are dropped to destroy a bridge. The probabilities of hitting the bridge by these bombs are 0.5, 0.2 and 0.1 respectively. Find the probability that the bridge is hit.

Answer 1

Answer:

Step-by-step explanation:

1st we have to find the relative probability.

P(0.5)= 0.5/(0.5+0.5+0.1+0.2)

P(0.2)=0.2/(0.2+0.5+0.8+0.1)

P(0.1)=0.1/(0.1+0.5+0.2+0.9)

P=p(0.5)+p(0.2)+p(0.1)=0.905

Answer 2

Answer:

The probability is $0.8$

Step-by-step explanation:

The probability that the first bomb will hit the bridge is $0.5=\frac{1}{2}$

The probability that the second bomb will hit the bridge is $0.2=\frac{1}{5}$

The probability that the third bomb will hit the bridge is $0.1=\frac{1}{10}$

Taking the LCM of these $3$ fractions,

$\frac{1}{2} =\frac{5}{10}$

$\frac{1}{5}= \frac{2}{10}$

$\frac{1}{10}=\frac{1}{10}$

Therefore the total probability is $\frac{5+2+1}{10}$ $=\frac{8}{10}$

Hence, total probability is $0.8$.

Simply put, probability refers to the likelihood of something occurring. We can talk about the probabilities of certain outcomes—how likely they are—when we're unsure about the outcome of an event.

Statistics is the study of events that are guided by probability.