Question

three bombs are dropped to destroy a bridge. the probabilities of hitting the bridge by these bomb are 0.5, 0.2 and 0.1 respectively. the probability that the bridge is hit is (a) 0.36 (b)0.64 (c) 0.80 (d) 0.90.

Answer 1

Answer:

0.36

Explanation:

is the answer of this question

Answer 2

Answer:

The answer is (C) 0.80

Explanation:

The probablity of the first bomb is

$\frac{5}{10}$  that is 0.5

The probablity of the second bomb is

$\frac{2}{10}$ that is 0.2

The probablity of the third bomb is

$\frac{1}{10}$ that is 1.0

The total probablity is 0.5+0.2+0.1=0.8