Three boys P, Q and R are to speak at a function along with 5 others. If all of them speak in random order, what is the probability that P speaks before Q and Q speaks before R
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Answer:
the proability is
Step-by-step explanation:
1/8 proabability of P speaking before Q
1/8 probability of Q speaking before R
Multiply that all together
you get 1/64
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