three boys sold garlands in the ratio of 2:3:4 together they sold 225garlands how many garlands did each boys sell
two numbers are in the ratio of 4:7 in the difference between the two numbers is 48find the sum of the two numbers
Answers
Answer:
Let the common multiple be x
Step-by-step explanation:
1st=1st boy =2x
2nd boy=3x
3rd boy=4x
Therefore
2x+3x+4x=225
9x=225
X=25
1st boy=2x=2*25=50 garlands
2nd boy=3*25=75
3rd boy =4x=4*25=100
2nd answer :let their common multiple be x
1st number =4x
2nd numbet=7x
Differnce =
7x-4x=48
3x=48
X=16
So we got
X=16
So sum of them is
:7x+4x=7*16+4*16
= 112+64
= 176
HOPE THIS WILL HELP YOU
Answer:
Step-by-step explanation:
Let the no. be x
2x +3x+4x =225
9x =225
x =225/9
x=25
1st boy = 2x25=50 garland
2nd boy =3x25=75 garlands
3rd boy =4x25=100 garlands
2nd answer :let their common multiple be x
1st number =4x
2nd numbet=7x
Differnce =
7x-4x=48
3x=48
X=16
So we got
X=16
So sum of them is
:7x+4x=7*16+4*16
= 112+64
= 176