Question

Three brands A, B and C of biscuits are available in packets of 12, 15 and 21

biscuits respectively. If a shopkeeper wants to buy an equal number of biscuits,

of each brand, what is the minimum number of packets of each brand, he should buy? ​

Answer 1

Given :-

Number of biscuits in brand A = 12

Number of biscuits in Brand B = 15

Number of biscuits in Brand C = 21

To Find :-

The minimum number of packets of each brand he should buy.

Analysis :-

Find the LCM of 12, 15 and 21 in order to get the minimum number of packets of each brand he should buy.

Solution :-

We know that,

LCM is multiple a number you get when you multiply a number by a whole number.

Since, we have to find the minimum number of packets of each brand,

We have to find the LCM of the given numbers,

LCM of 12, 15 and 21

$\sf LCM = 2\times2\times3\times5\times7$

$\sf LCM=420$

Therefore, there are 420 number of packets of each brand he should buy.

Answer 2

Answer:

✡ Given ✡

✏ No. of biscuits available in brand A = 12

✏ No. of biscuits available in brand B = 15

✏ No. of biscuits available in brand C = 21

✡ To Find ✡

➡ What is the minimum number of packets of each brand, he should buy?

✡ Solution ✡

✏ This is based on LCM property.

▶ So the LCM of 12, 15 and 21 will be,

=> 2 × 2× 3 × 5 × 7

=> 420

✏ Thus, required minimum no of packet of each brand will be,

⬛ Brand A = $\dfrac{420}{12}$ = 35

⬛ Brand B = $\dfrac{420}{15}$ = 28

⬛ Brand C = $\dfrac{420}{21}$ = 20

➡ Hence, the minimum number of packets of each brand will be

✳ Brand A = 35

✳ Brand B = 28

✳ Brand C = 20