Three bulbs are chosen at random from 15 bulbs of which 5 are defective. What is the probability that one of the three bulbs is defective? Using probability distribution formula
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Probability of getting undefective bulb = 1/10
Probability of getting 2 undefective bulb = 2/10 = 1/5
Probability of getting defective bulb = 1/5
Probability of getting 2 undefective and 1 defective bulb = 1/5+1/5 = 2/5
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