three bulbs are connected in series combination having wattage 25 Watt,40 watt and 60 watt and having potential difference of 6 volt.Write the order of brightness of the bulb when key is closed with explanation....
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thus , R= V^2/P
Let bulbs of 25W, 40W , and 60W have resistance R(1) ,R (2) and R (3)
R (1)= 6*6/25 =1.44 ohm
R (2) = 6*6/40=0.9 ohm
R (3)= 6*6/60=0.6 ohm
The bulb with highest resistance will glow the brightest, thus bulb with 25 W is the brightest
Answer is 25 W
siya0123:
Thanks but according to the question potential difference is 6V
now sol is according to ur question
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