Physics, asked by siya0123, 1 year ago

three bulbs are connected in series combination having wattage 25 Watt,40 watt and 60 watt and having potential difference of 6 volt.Write the order of brightness of the bulb when key is closed with explanation....

Answers

Answered by anmolsoni

thus , R= V^2/P

Let bulbs of 25W, 40W , and 60W have resistance R(1) ,R (2) and R (3)

R (1)= 6*6/25 =1.44 ohm

R (2) = 6*6/40=0.9 ohm

R (3)= 6*6/60=0.6 ohm

The bulb with highest resistance will glow the brightest, thus bulb with 25 W is the brightest

Answer is 25 W

siya0123: Thanks but according to the question potential difference is 6V

anmolsoni: now sol is according to ur question

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