Three bulbs of 100 W each, a fan of 1500 W and an electric iron of 1100 W are
daily operated for 5 hours, 7 hours and 2 hours respectively. What will be the total
electrical consumption expenses of these appliances for the month of April. [The
electrical company charges 5 */ unit]
(1) 1500 (2) 1080 (3) 2130 (4) 2080
Answers
Answer:
An electric iron of 1,100 W is operated for 2 hours daily. What will be the electrical consumption expenses for that in the month of April (the electric company charges Rs 5 per unit of energy)?
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8 Answers

Alladi Jagannath, Electrical Engineer, from BITS Pilani, retired from Switchgear R&D, L&T
Answered May 11, 2018 · Author has 516 answers and 1M answer views
The total number of hours=2*30=60
Total energy consumption=60*1,1= 66 kWh
Energy cost = 66*5= Rs 330
It is to be noted that the iron has a thermostat, which trips when the set temperature is reached. The thermostat also resets when the temperature falls. This results in a duty cycle with an “on” period followed by an “off” period. This would result in a substantially lower energy consumption.
6.2K views
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Aayush Kumar, Engineer at Electronics Corporation of India Limited (2018-present)
Answered May 10, 2018
Wattage= 1100 W=1.1 kW
Time for which it is operated in April= 2 hrs a day x 30 days= 60 hrs
Total units (kW-hr)= 1.1x60=66 kW-hr
Cost= Per unit cost * No. of units= 5x66= Rs. 330
6.7K views
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Sanjeevani Karambalkar, works at Sharekhan
Answered October 12, 2019
Given:P=1100W=1.1Kw,T=2hr,Days on April=30 days
ToFind:Energy,Rate
Solution: E=Power×Time
E=1.1×2×30
E=1.1×60
E=66 Unit
Rate=Unit×Charge
Rate=66×5
Rate=RS 330
Rate of 66 unit electricity is RS 330
1K views

Tarun Vaghasiya, studied Electrical Engineering
Answered May 13, 2018
Originally Answered: An electric iron of 1100 w is operated for 2 hours daily. What will be the electrical consumption expenses for that in the month of April (the electric company charges rs 5 per unit of energy)?
1100w*2(hours daily)=2200w per day.
Now for April total days are 30.
So monthly consumption is 2200*30= 66000w/1000w = 66 units.
Now for a unit company charges about 5rs so the monthly bill will be around 66*5=330rs/-
731 views
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Pei Fu, lives in Zhengzhou, Henan, China
Answered July 25, 2018 · Author has 194 answers and 171.6K answer views
30 days in April
Consume 1100W × 2 = 2200W = 2.2KW per day
Consumption in April 2.2×30=66KW·h
Money 66×5=330
Answer:
Explanation:
this question was asked in ntse maharashtra!
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