Physics, asked by rohansp346, 5 months ago

Three bulbs of 100 W each, a fan of 1500 W and an electric iron of 1100 W are
daily operated for 5 hours, 7 hours and 2 hours respectively. What will be the total
electrical consumption expenses of these appliances for the month of April. [The
electrical company charges 5 */ unit]
(1) 1500 (2) 1080 (3) 2130 (4) 2080

Answers

Answered by MehakThakran
1

Answer:

An electric iron of 1,100 W is operated for 2 hours daily. What will be the electrical consumption expenses for that in the month of April (the electric company charges Rs 5 per unit of energy)?

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8 Answers

Alladi Jagannath, Electrical Engineer, from BITS Pilani, retired from Switchgear R&D, L&T

Answered May 11, 2018 · Author has 516 answers and 1M answer views

The total number of hours=2*30=60

Total energy consumption=60*1,1= 66 kWh

Energy cost = 66*5= Rs 330

It is to be noted that the iron has a thermostat, which trips when the set temperature is reached. The thermostat also resets when the temperature falls. This results in a duty cycle with an “on” period followed by an “off” period. This would result in a substantially lower energy consumption.

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Other Answers

Aayush Kumar, Engineer at Electronics Corporation of India Limited (2018-present)

Answered May 10, 2018

Wattage= 1100 W=1.1 kW

Time for which it is operated in April= 2 hrs a day x 30 days= 60 hrs

Total units (kW-hr)= 1.1x60=66 kW-hr

Cost= Per unit cost * No. of units= 5x66= Rs. 330

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Sanjeevani Karambalkar, works at Sharekhan

Answered October 12, 2019

Given:P=1100W=1.1Kw,T=2hr,Days on April=30 days

ToFind:Energy,Rate

Solution: E=Power×Time

E=1.1×2×30

E=1.1×60

E=66 Unit

Rate=Unit×Charge

Rate=66×5

Rate=RS 330

Rate of 66 unit electricity is RS 330

1K views

Tarun Vaghasiya, studied Electrical Engineering

Answered May 13, 2018

Originally Answered: An electric iron of 1100 w is operated for 2 hours daily. What will be the electrical consumption expenses for that in the month of April (the electric company charges rs 5 per unit of energy)?

1100w*2(hours daily)=2200w per day.

Now for April total days are 30.

So monthly consumption is 2200*30= 66000w/1000w = 66 units.

Now for a unit company charges about 5rs so the monthly bill will be around 66*5=330rs/-

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Pei Fu, lives in Zhengzhou, Henan, China

Answered July 25, 2018 · Author has 194 answers and 171.6K answer views

30 days in April

Consume 1100W × 2 = 2200W = 2.2KW per day

Consumption in April 2.2×30=66KW·h

Money 66×5=330

Answered by jagtapswapnali010
0

Answer:

Explanation:

this question was asked in ntse maharashtra!

I AM WRONG

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