Question

Three bulbs of hundred watt each ,a fan of 1500 w and an electric iron of 1100 w are daily operated for 5 hrs,7 hrs and 2 hrs respectively. What will be the total electrical consumption expenses of these appliances for the month of April.(the electrical company charges 5 rupees per unit)

Answer 1

Formula Used

• E = P × t

Where,

E is the Energy Consumed

P is the Power

t is the time used for

1 unit = 1000wh

Solution:-

Firstly we calculate the Energy Consumed by 3 bulbs in 5 hours.

EB is the Energy Consumed by Bulb

Substitute the value we get

→ EB = 3 × 100 × 5

→ EB = 1500 wh

→ EB (in unit) = 1500/1000 = 1.5 unit

Total energy consumed by Bulb in Month of April

→ EB = 30 × 1.5 = 45 Unit -----------(i)

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Now, Calculating the energy consumed by the Fan in 1 day which is used for 7 hours

EF is the energy consumed by the fan

Substitute the value we get

→ EF = 7× 1500

→ EF = 10500Wh

→ EF (in unit) = 10500/1000 = 10.5 unit

Energy Consumed by fan in 30 days

→ EF = 30×10.5 = 315 Unit ----------(ii)

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Now, Calculating the Energy Consumed by iron in 1day which is used for 2 hour daily.

EI is the Energy Consumed by Iron.

Substitute the value we get

→ EI = 1100×2

→ EI = 2200

→ EI (in Unit) = 2200/1000 = 2.2 unit

Energy consumed by Iron in 30 days

→ EI = 2.2 ×30 = 66 unit -----------------------(iii)

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And, Calculating the total energy consumed by given appliances .

• Total Energy = Energy Consumed by Bulb + Energy Consumed by Fan + Energy Consumed by Iron

Substitute the value we get

→ E = EB + EF + EI

→ E = 45 + 315 + 66

→ E = 426 unit

Total energy consumed by appliances is 426 units

And it is given that the rate of charges = Rs 5 Per Unit

→ Total Charges = 5×426

→ Total Charge = Rs 2130

Therefore, Total charges of the electric is Rs 2130 .

Hence, Required option is (c) Rs 2130 .

Answer 2

$\huge{\boxed{\rm{Question}}}$

Three bulbs of hundred watt each ,a fan of 1500 w and an electric iron of 1100 w are daily operated for 5 hrs, 7 hrs and 2 hrs respectively. What will be the total electrical consumption expenses of these appliances for the month of April. (The electrical company charges 5 rupees per unit). Options are given below

⑴ Rupees 1500

⑵ Rupees 1080

⑶ Rupees 2130

⑷ Rupees 2080

$\huge{\boxed{\rm{Answer}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• There are three bulbs of 100 watt.

• There is a fan is of 1500 watt.

• There is an electric iron of 1100 watt.

• Three bulbs are worked for 5 hrs daily.

• The fan is work for 7 hrs daily.

• The electric iron is used for 3 hrs daily.

• The electrical company charges 5 rupees per unit.

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• The total electrical consumption expenses of these appliances for the month of April.

$\large{\boxed{\boxed{\sf{Solution}}}}$

• The total electrical consumption expenses of these appliances for the month of April = Rupees 2130.

$\large{\boxed{\boxed{\sf{Using \: formula}}}}$

• E = P × t

• Total consumed energy atq = Energy consumed by bulb + Energy consumed by fan + Energy consumed by electric iron.

$\large{\boxed{\boxed{\sf{These \: also \: means}}}}$

• E means consumed energy.

• P means power.

• t means time used for.

$\large{\boxed{\boxed{\sf{Some \: required \: knowledge}}}}$

• 1 unit = 1000 watts.

$\large{\boxed{\boxed{\sf{Assumptions}}}}$

• Let B as the energy consumed by that 3 bulbs in 5 hours.

• Let F as the energy consumed by that bulb in 7 hours.

• Let I as the energy consumed by that iron in 2 hours.

$\large{\boxed{\boxed{\sf{What \: does \: the \: question \: says}}}}$

$\large{\boxed{\boxed{\sf{Let's \: understand \: the \: concept \: 1st}}}}$

• This question says that there are three bulbs of 100 watt. There is a fan is of 1500 watt. There is an electric iron of 1100 watt. Three bulbs are worked for 5 hrs daily. The fan is work for 7 hrs daily. The electric iron is used for 3 hrs daily. The electrical company charges 5 rupees per unit. Afterwards, this is also given that the electrical company charges 5 rupees per unit). Options are given below for help !
• ⑴ Rupees 1500
• ⑵ Rupees 1080
• ⑶ Rupees 2130
• ⑷ Rupees 2080

$\large{\boxed{\boxed{\sf{How \: to \: solve \: this \: question}}}}$

$\large{\boxed{\boxed{\sf{Let's \: see \: the \: procedure \: now}}}}$

• To solve this question, we have to use our assumptions 1 by 1 afterthat using these assumptions we have to find the consumed energy of 1 appliance afterthat to find the consumed energy of 2 appliance afterthat to find the consumed energy of 3 appliance. ( Putting the values ) Afterwards, finding the total energy consumed by the given appliances. Hence, we have done.

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

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Firstly we have to find the energy consumed by that 3 bulbs in 5 hours.

Let B as the energy consumed by that 3 bulbs in 5 hours.

Putting the values we get the following results,

B = 3 × 100 × 5

B = 300 × 5

B = 1500 watts.

But 1 unit = 1000 watts, hence

B = 1500 / 1000

B = 15 / 10

B = 3 / 2

B = 1.5 watts.

Now, total energy consumed by bulb in Month of April.

B = 30 × 1.5

B = 45 units Eǫᴜᴀᴛɪᴏɴ ①

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Now, we have to find the energy consumed by that fan in 7 hours.

Let F as the energy consumed by that bulb in 7 hours.

Now, putting the values we get the following results.

F = 1500 × 7

F = 10500 watts.

But, 1 unit = 1000 watts, hence

F = 10500 / 1000

F = 105 / 100

F = 21 / 20

F = 10.5 watts

Now, total energy consumed by fan in Month of April.

F = 30 × 10.5

F = 315 units Eǫᴜᴀᴛɪᴏɴ ②

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Now, we have to find the energy consumed by that electric iron in 2 hours.

Let I as the energy consumed by that iron in 2 hours.

Now, putting the values we get the following results.

I = 1100 × 2

I = 2200 watts

But, 1 unit = 1000 watts, hence

I = 2200 / 1000

I = 22 / 10

I = 11 / 5

I = 2.2 watts

Now, total energy consumed by iron in Month of April.

I = 30 × 2.2

I = 66 units Eǫᴜᴀᴛɪᴏɴ ③

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Now, finding the total energy consumed by the given appliances

Formula : Energy consumed by bulb + Energy consumed by fan + Energy consumed by electric iron.

Putting the values according to the formula we get the following results.

E = B + F + I

E = 45 + 315 + 66

E = 360 + 66

E = 426 units

Hence, E = 426 unit's.

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But it is also given that the electrical company charges 5 rupees per unit hence, continuing....

Total charges = 426 × 5

Total charges = 2130 rupees.

So, 2130 rupees are total charges.

Means option ⑶ is correct option.

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