Question

Three bullets are fired successively at 30º, 45º and 60º with the horizontal and with same velocity. If their horizontal ranges are R1, R2 and R3 respectively, then

Answer 1

Answer:

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Explanation:

Answer 2

Answer:

Range, R=3km

Angle of projection, =30

o

Acceleration due to gravity, g=9.8m/s

2

Horizontal range for the projection velocity u

0

, is given by the relation:

R=

g

u

o

2

Sin 2θ

3=

g

u

o

2

Sin 60

0

g

u

o

2

=2

3

.......(i)

The maximum range (Rmax) is achieved by the bullet when it is fired at an angle of 45 with the horizontal, that is, Rmax = u

o

2

/ g ....(ii)

On comparing equations (i) and (ii), we get:

R

max

=2×1.732=3.46 km

Hence, the bullet will not hit a target 5 km away.