three buoys k l and m show the course of a boat race. M K= 4 km,KL = 9km and angle MKL =108
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Given : three buoys k l and m show the course of a boat race.
MK= 4 km, KL = 9km and angle MKL =108°
To Find : Distance ML
Solution:
cosine rule
c² = a² + b² - 2abCosC
a = MK = 4 km
b = KL = 9 km
∠C = ∠MKL =108°
c = ML
(ML)² = 4² + 9² - 2(4)(9) Cos 108°
=> (ML)² = 16 + 81 - 72 (-0.309)
=> (ML)² = 16 + 81 - 72 (-0.309)
=> (ML)² =119.248
=> ML = 10.92 km
Distance ML = 10.92 km
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