Three cakes have weights 5 lb, 7 lb, and 8 lb. Each cake is to be cut into pieces, such that all the pieces have equal weight and each piece must have the maximum possible weight. Find the number of guests who can be served, if each piece is served to one guest?
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Given:
Weight of first cake = 5 lb
Weight of second cake = 7 lb
Weight of third cake = 8 lb
To find:
The number of guests who can be served
Calculation:
To get the maximum weight for each piece, take the H.C.F of 5, 7, 8. The H.C.F of 5, 7, 8 is 1
Pieces given by first cake = 5/1 = 5
Pieces given by second cake = 7/1 = 7
Pieces given by third cake = 8/1 = 8
Total number of pieces = 5+7+8
= 20
20 guests can be served with one piece each
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