three cans contain 12 liters, 16 liters and 24 liters of milk. A jug is filled with whole number of times from each cane. What is the greatest capacity of the jug.
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I assume that each mug is full and there are no left overs.
Factor each can capacity and determine what is “common to all three:
12 = 2 x 2 x 3
16 = 2 x 2 x 2 x 2
24 = 2 x 2 x 2 x 3
2 x 2 is common to all three can capacities, therefore, 4 is the maximum mug size.
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