Question

three capacitance 2uf , 3uf and 6 uf are connected in series with a 10 volt battery then charge on 3uf capacitance is ​

Answer 1

Answer:

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Answer 2

The charge on $3\ \mu F$capacitance is ​$10\ \mu C$.

Explanation:

Given that,

Capacitance, $C_1=2\ \mu F$

Capacitance, $C_2=3\ \mu F$

Capacitance, $C_3=6\ \mu F$

Voltage, V = 10 volt

In series  combination of capacitors the equivalent capacitance is given by :

$\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}$

$\dfrac{1}{C}=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}$

$C=1\ \mu F$

In series combination the charge remains constant,

So,charge on $3\ \mu F$ capacitance is:

$Q=CV$

$Q=1\times 10=10\ \mu F$

So, the charge on $3\ \mu F$capacitance is ​$10\ \mu C$. Hence, this is the required solution.

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Series combination of capacitance

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