Three capacitor 1uf, 2uf, 3uf are connected in series with 230volts. what is the charge on eache capacitor
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1/Ceqv=(1/1)+(1/2)+(1/3)
1/Ceqv=11/6
Ceqv=6/11
as we know, q=CV
q=(6/11)×230 Coulomb
this will be the charge on each capacitor
1/Ceqv=11/6
Ceqv=6/11
as we know, q=CV
q=(6/11)×230 Coulomb
this will be the charge on each capacitor
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0
Explanation:
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