Question

Three capacitor 8 micro farah 16 microfarad.32 microfarad are connected in series what is the total c

Answer 1

HELLO THERE!

Note: When three capacitors are connected in series, the method of finding the equivalent capacitance is just like the method of finding equivalent resistance if three resistors were connected in parallel.

So, we have:

$\frac{1}{C_{eq}} = \frac{1}{8} + \frac{1}{16} + \frac{1}{32}\\\\=\frac{7}{32}\\\\\implies C_{eq} = \frac{32}{7} \mu F$

Answer 2

When three capacitors are connected in series, the method of finding the equivalent capacitance is just like the method of finding equivalent resistance if three resistors were connected in parallel.

So, we have:

eq1 = 8

1 + 16

1 + 32

1= 327⟹C

eq = 732 μF