Question

Three capacitor 8 microfarad 16 microfarad.32 microfarad are connected in series what is the total capacitance

Answer 1

Note: When three capacitors are connected in series, the method of finding the equivalent capacitance is just like the method of finding equivalent resistance if three resistors were connected in parallel.

So, we have:

\begin{lgathered}\frac{1}{C_{eq}} = \frac{1}{8} + \frac{1}{16} + \frac{1}{32}\\\\=\frac{7}{32}\\\\\implies C_{eq} = \frac{32}{7} \mu F\end{lgathered}Ceq1=81+161+321=327⟹Ceq=732μF