Question

three capacitor of capacitance 2uf are connected in series. fine result capacitance ​

Answer 1

Your answer:

Formula for capacitance in series

$\frac{1}{C_s_e_r_i_e_s}$ = $\frac{1}{C_1} +\frac{1}{C_2} +....$

Now, your answer is:

$\frac{1}{2} +\frac{1}{2}+\frac{1}{2} = \frac{3}{2}$ = $1.5\mu F$

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