Question

three capacitors are connected in series. derive an expression for the equivalent capacitors
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Answer 1

Since q= cv

Therefore for

Capacitor 1 q1 =c1v1

Or v1 = q1/c1

Q2=c2v2 or v2 = q2/c2

And v3 = q3/c3

Here in series q1=q2 =q3 =q and व net v1+v2+v3

Hence v net = q/c1+q/c2 + q/c3

V net = q(1/c1+1/c2+1/c3)

But v net is qx c net

Therefore q x 1/c net = q x (1/c1+1/c2 + 1/ c3)

Q will be cancelled out therefore

1/c net = 1/c1 + 1/c2 + 1/c3