Question

Three capacitors are connected with the source of electromotive force E
as shown in the figure. Then, the energy drawn from the source is
​

Answer 1

$\large\mathcal{\underbrace{\red{SoLUTIoN:-}}}$

FORMULA :-

✍️ Capacitors in Series :-

$\rm{\boxed{\dfrac{1}{C_{eq}}\:=\:\dfrac{1}{C_1}\:+\:\dfrac{1}{C_2}\:+\:\dfrac{1}{C_3}\:+..........+\:\dfrac{1}{C_n}\:}}$

✍️ Capacitors in Parallel :-

$\rm{\boxed{C_{eq}\:=\:C_1\:+\:C_2\:+\:C_3\:+..........+\:C_n\:}}$

☞ where,

• $\rm{C_{eq}}$ = Equivalent capacitance .

CaLCULaTION :-

✴️ For calculation of Equivalent capacitance, see the attachment picture .

✍️ Equivalent capacitance = 3 C

➜ Here,

• $\rm{C_{eq}}$ = ‘3C’

• potential difference (V) = ‘E’

$\bigstar\:\rm{\purple{\boxed{Energy\:=\:\dfrac{1}{2}\:C_{eq}\:V^2\:}}}$

$\rm{\implies\:Energy\:=\:\dfrac{1}{2}\:\times{3C}\:\times{E^2}\:}$

$\rm{\boxed{\implies\:Energy\:=\:\dfrac{3}{2}\:CE^2\:}}$

$\checkmark\:\bf{\blue{\boxed{(B)\:\dfrac{3}{2}\:CE^2\:}}}$