Three capacitors C1, C2 and C3 are connected to a 6V battery, as shown in figure. Find the charges on the three
capacitors. in detail please
Answers
Given: Three capacitors C₁, C₂ and C₃ are connected to a 6V battery shown in figure.
To Find: charges on the three capacitors.
Solution:
STEP 1:
C₂ and C₃ are connected in parallel.
so add these capacitance in parallel, we get:
= C₂ + C₃
= 5 + 5 = 10μF
so, = 10μF (shown in fig. 2 attached)
Step 2:
Now, and C₁ are in series.
so add these capacitance in series, we get:
= () + (
= (1/10) + (1/10)
= 5μF (shown in fig. 3 attached)
Step 3:
Now in fig. 3 we have only voltage source and capacitance of 5μF.
we know that Q = CV ..................eqn 1
here, C = 5μF
and V = 6V
Put the value of C and V in eqn 1, we get;
Q = 5 × 6 =30μC
step 4:
Now, as the capacitor C₂ and C₃ are of equal value so charge will equally distribute among them.
So, 15μC charge will flow through C₂ and C₃
total 30μC charge will flow through C₁
charge distribution is shown in fig.4 attached.
Answer:
Charge (Q₁) flowing through C₁ = 30μC
Charge (Q₂) flowing through C₂ = 15μC
Charge (Q₃) flowing through C₃ = 15μC
Answer:
Hope it helps
Explanation: