CBSE BOARD XII, asked by yadavkomal2909, 23 hours ago

Three capacitors each of capacity 4 μF are to be connected in such a way that then resultant capacity is 6 μF. This can be done by:

Answers

Answered by VanXodus
0

Answer:

Connecting two in series and one in parallel

Explanation:

Explanation is provided in the attached image

Hope it helps!

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