Question

Three capacitors of capacitances 6 µF each are available. The minimum and maximum capacitances, which may be obtained are
(a) 6 µF, 18 µF
(b) 3 µF, 12 µF
(c) 2 µF, 12 µF
(d) 2 µF, 18 µF.

Answer 1

(d) The minimum and maximum capacitances can be obtained as 2 µF and 18 µF.

Explanation:

• Please note, the minimum capacitance can be obtained by connecting all capacitors in series. Hence this can be calculated as follows:-

          1C = 1/6+1/6+1/6=1/2  

          ⇒⇒    C = 2 µF

• Also the maximum capacitance can be obtained by connecting all capacitors in parallel. Hence this can be calculated as follows:-

          C = 6 + 6 + 6 = 18 µF