Question

three capacitors of equal capacitance ,when connected in series have a net capacitance of c1 and when connected in parallel have a capacitance of c2 what will be the value of c1/c2?

Answer 1

Answer:

For series combination,

1/C1=1/C+1/C+1/C [ Since all capacitors have equal capacitances]=3/C Or

C1=C/3−−−(i)

For parallel combination,

C2=C+C+C=3C−−−(ii)

Now,C1/C2=C/3/3C=C/3×1/3C=1/9

Answer 2

The value of c1/c2 is 1/9.

Given,

Three capacitors of equal capacitance.

The equivalent capacitance when connected in series = c1

The equivalent capacitance when connected in parallel = c2

To Find,

The value of c1/c2.

Solution,

Let the capacitance of each capacitor be c.

When the capacitors are connected in series

1/c1 = 1/c+1/c+1/c

1/c1 = 3/c

c1 = c/3

Now, the capacitors are connected in parallel

c2 = c+c+c

c2 = 3c

Now,

c1/c2 = (c/3)/3c = 1/9

Hence, the value of c1/c2 is 1/9.

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