three capacitors of three different capacitance are connected in series,then the equivalent capacitance will be
A. equal to that of the greatest capacitance.
B. equal to that of the smallest capacitance.
C. less than that of the smallest capacitance.
D. Greater than that of the greatest capacitance.
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Correct Option is (C).
Now we know that equivalent capacitance of three capacitors in series can be given by,
1/C = 1/C1 + 1/C2 + 1/C3
Now take any three different values and you will find that equivalent capacitance will be less than that of the smallest capacitance value.
"Thanks"
Now we know that equivalent capacitance of three capacitors in series can be given by,
1/C = 1/C1 + 1/C2 + 1/C3
Now take any three different values and you will find that equivalent capacitance will be less than that of the smallest capacitance value.
"Thanks"
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