Physics, asked by sathawanevedant2503, 2 months ago

Three capacitors or capacitances 2 pF, 3 pF and 6 pF are connected in series .The equivalent capacitance of the combination is a)0.5 pF b) 1 pF c)1.1 pF d)11 pF​

Answers

Answered by rajvins
8
(a) For parallel combination, C
eq

=C
1

+C
2

+C
3

=(2+3+4)pF=9pF
(b) q=V×C
for parallel array, V remains the same across each capacitor.
for C=2 pF
q
1

=VC=100×2×10
−12
=2×10
−10
C
for C=3 pF
q
2

=VC=100×3×10
−12
=3×10
−10
C
for C=4 pF
q
1

=VC=100×4×10
−12
=4×10
−10
C
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