Question

Three capacitors, whose capacitances are 4 µF, 6 µF and 12 µF respectively, are connected in series order, then find the equivalent capacitance of the combination.​

Answer 1

Answer:

2 μF

Explanation:

When the capacitors are connected in series , we use the following formula

1/Equivalent capacitance = 1/C1 + 1/C2 + 1/C3

= 1/4 + 1/6 + 1/12 = 6/12 = 1/2.

Therefore the equivalent capacitance = 2 μF.