Three capacitors with capacitance 3µF, 4µF, 5µF are arranged in parallel combination with a battery of 6 V. Find the total capacitance and the quantity of charge on each plate of the capacitor.
Answers
Answer:
given that:
capacitor, C1=3µF , C2=4µF, C3=5µF
voltage, V'=6V
find: Total capacitance, C=?
charge on each plate of capacitor, Q1, Q2,Q3=?
in case of parallel,
total capacitance= C1+C2+C3
C=3µF+4µF+5µF
C=12µF
we know that, the voltage is same in parallel in all plates of capacitor
charge on 1st capacitor, Q1=C1.V
=(3).(6)
=18µC
charge on 2nd capacitor, Q2=C2.V
=(4).(6)
=24µC
charge on 3rd capacitor, Q3=C3.V
=(5).(6)
=30µC