three cards are drawn successively without replacement from a pack of 52 well shuffled cards what is the probability that first two cards are kings and the third card drawn is an Ace
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The probability of the cards is 2/5225.
Number of sample space in the cards P(S1) = 52
The sample space in second time, without replacement = P (s2) = 51
Similarly in third time the replacement will be = P(s3) = 50
A dependent probability is a probability where the number of the sample space can be change as per the question.
Probability of a king =P ( K1) = n(K1) / n(s1) = 4/52
Probability of second king = n(K2) / n(s2) = 3/51
Probability of an ace = n(A) / n(s3) = 4/50
Therefore the probability, P(of event) will be
P {P(K1) and P(K2) and P(K3)}
Multiplicating the principle, P(E)
= 4/52 × 3/51 × 4/50
= 2/5225
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