Three cars are for sale. Car a- £12380, car b-£16760, car c-£14580 th price of each car is rounded to the nearest 100. Which price changes by the greatest amount? You must show your working.
Answers
The answer is car b.
All numbers are rounded up as the 10s are higher than 50.
A) £12380 rounded to £12400
£20 difference
B) £16760 rounded to £16800
£40 difference
C) £14580 rounded to £14600
£20 difference
Car B price would be change by greatest amount.
Step-by-step explanation:
Price of Car A = £12380
Price of Car B = £16760
Price of Car C = £14580
We need to round the price to nearest 100 and check which price of car would be affected greatly.
Now the numbers which are greater than 5 in tenth place are added by 1 in hundred place which makes them to nearest hundred.
£ 12380 when rounded to nearest hundred becomes £12400
Hence New Price of Car A = £12400
Amount changed is of £20.
£ 16760 when rounded to nearest hundred becomes £16800
Hence New Price of Car A = £16800
Amount changed is of £40.
£ 14580 when rounded to nearest hundred becomes £14600
Hence New Price of Car A = £14600
Amount changed is of £20.
Hence Car B changes by great amount which is £40.