Three cells connected in parallel with their like poles connected in parallel with their
like poles connected together with wires of negligible resistance. The e.m.f.s of the
cells are 2V, 3V and 4V respectively and their internal resistance are
1 ohms, 2 ohms and 3 ohms
respectively. Find the current through each branch (or each cell).
Answers
Explanation:
Let the current coming out of cell 4 v be i1
Let the current coming out of cell 3v be i2
Then the current going into cell 2v is = i1+i2
The potential available outside the cells = same
So 4-3 i1 = 3-2 i2 = 2=i1
= 3 i1-2 i2 =1
= i1+2 i2 =1
solving them : i1 = 0.05 A
i2 = 0.25 A
Current through the 2v cell is 0.75 A
So your ans is o.75 Amperes
Answer:
Explanation:
Let the current coming out of cell 4 v be i1
Let the current coming out of cell 3v be i2
Then the current going into cell 2v is = i1+i2
The potential available outside the cells = same
So 4-3 i1 = 3-2 i2 = 2=i1
= 3 i1-2 i2 =1
= i1+2 i2 =1
solving them : i1 = 0.05 A
i2 = 0.25 A
Current through the 2v cell is 0.75 A
So your ans is o.75 Amperes