Question

Three chairs and two tables cost 5400 rs. Four chairs and three tables cost 7800 rs Find cost of one table . *​

Answer 1

Answer:

hey here is ur answer champ

Step-by-step explanation:

so here we go

now let cost of one chair be x rs and that one table be y rs

now according to first condition ,,

3x+2y=5400 (1)

according to second condition,,

4x+3y=7800 (2)

now multiply (1) by 4 and that of (2) by 3 we get

12x+8y=21600 (3)

and 12x+9y=23400 (4)

so now subtract (3) from (4)

we get

y=1800

so hence cost of one table is 1800 rs

I hope u cracked the logic now

please mark my answer as brainliest

Answer 2

Answer:

let table be "a" and chairs be "b'

so, 3a+2b =5400 and 4b+3a = 7800

Step-by-step explanation:

(4b+3a )= 7800

-2*( 3a+2b )= 2(5400)

-------------------------------------

-3a= -3000

therefore , a =1000

so , by putting it eq

4b+3a=7800

4b+ 3*1000=7800

4b+ 3000=7800

4b=7800-3000

4b=4800

b=1200

3a +2b=5400

3*1000+2*1200=5400

3000+2400=5400

5400=5400

lhs=rhs

therefore the cost of is 1000 rs