Question

Three characteristics assort independently in one species of insect: red eyes (r) are dominant to black eyes (r). Blue wings (b) are dominant to white wings (b). Green bodies (g) are dominant to yellow bodies (g). A cross is made between two heterozygous insects (rrbbgg). What is the probability that the offspring will be homozygous dominant for all three characteristics?

Answer 1

Answer:

$\frac{1}{64}$

Explanation:

We need to cross

RrBbGg * RrBbGg

Doing individual crosses we get probability of homozygous dominant traits to be

$\frac{1}{4}$

for all characters (RR out of RR Rr rR rr & so on for all characters)

Therefore Probability of getting RRBBGG is

$\frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = \frac{1}{64}$