three charge +4q , Q and q are placed in a straight line of length l at point distance 0 , l / 2 and l respectively what should be the value of Q in order to make the net force on q to be 0 ?
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Hi..
two force are acting on q ,one due to 4q and second due to Q
F1 = 1/4∏ε (4q)q/l2
F2 = 1/4∏ε (Q)q/(l/2)2
= 1/4∏ε (4Q)q/l2
F1 +F2 =0
1/4∏ε (4q)q/l2 + 1/4∏ε (4Q)q/l2 =0
Q=-q..
Hope this helps u!!
two force are acting on q ,one due to 4q and second due to Q
F1 = 1/4∏ε (4q)q/l2
F2 = 1/4∏ε (Q)q/(l/2)2
= 1/4∏ε (4Q)q/l2
F1 +F2 =0
1/4∏ε (4q)q/l2 + 1/4∏ε (4Q)q/l2 =0
Q=-q..
Hope this helps u!!
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