Three charged particles having charges q,-2q and q are placed at points (-a,0),(0,0) and (a,0) respectively.the expression for electric potential at (0,r) is
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Answer ⇒ 2kqa²/r(r² - a²)
Explanation ⇒ At a point P(r,0), Potential will be due to three charges namely q, -2q , and q.
Now,
Potential at Point P due to -2q = k(-2q)/r = -2kq/r
Potential at point p Due to q = kq/(r-a) + kq/(r + a)
= kq[r + a + r - a]/(r² - a²)
= 2kqr/(r² - a²)
Net Potential = Potential at Point P due to -2q + Potential at Point P due to q
∴ Net Potential = -2kq/r + 2kqr/(r² - a²)
= 2kq[-1/r + r/(r² - a²)]
= 2kq[-r² + a² + r²]/r(r² - a²)
= 2kqa²/r(r² - a²)
Hence, the net potential at point P is 2kqa²/r(r² - a²).
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