Question

Three charged particles (their sign are shown) move along the path in a uniform electric field
as shown. In each of three cases, state whether the potential energy increases or decreases?
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Answer 1

Answer:

The electric field E is uniform inside the parallel plates.

The bending (deviation) from a straight line path depends on the Electric field perpendicular to velocity.

 For the same velocity and electric field, the bending depends on charge per mass ratio. 

The charged particle 3 bends most. So its charge/mass ratio is the highest.The particle 3 moves towards negative charges.

So it is a positive charge.Particles 1 and 2, move towards positive charges. So they are negative.

hope these will help you...

Answer 2

explanation

for particle A:- (-)

=>>>>>>>>>>≥> direction of electric field

<<<<<<<<<≤=. direction of negatively charged A

thus it's velocity decreases => kinetic energy decreases=> potential energy increases

for particle B:- (+)

=>>>>>>≥>>> direction of electric field.

<<<<<<≤<<<= direction of positively charged B

thus it's velocity increases => kinetic energy increases => potential energy decreases

for particle C:- (+)

=>>>>>>>>>> direction of electric field

=>>>>>>>>>> direction of positively charged C

thus it's velocity decreases => kinetic energy decreases => potential energy increases