Three charges + 20 esu, -25 esu and +50 esu are placed at the
points A, B and C respectively on a straight line. What force will
act on the charge placed at B ? Given AB = 10 cm; BC = 15 cm.
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Answer:
i solved it (easy one) here are the snaps ...
i numbered corners as 1,2,3 & 4
i calculate force on 2 due to 1,3 & 4
F21 = force on 2 due to 1
F23 = force on 2 due to 3
F is resultant of F21 & F23 directed towards diagonal
add them by vector resultant
F24 is also in the same direction along diagonal
so net force
Fnet = F24 + F
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