Three charges +4q , q and +q are placed in a straight line with q midway in between the other two charges. if net force on +q is zero, then q must be
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heya.......
tysm....@gozmit
two force are acting on q ,one due to 4q and second due to Q
F1 = 1/4∏ε (4q)q/l2
F2 = 1/4∏ε (Q)q/(l/2)2
= 1/4∏ε (4Q)q/l2
F1 +F2 =0
1/4∏ε (4q)q/l2 + 1/4∏ε (4Q)q/l2 =0
Q=-q
tysm....@gozmit
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