Physics, asked by abdalla234, 1 month ago

Three charges are at the corners of an equilateral triangle,
as shown in Fig. (1). (a) Calculate the electric field at the
position of the 2 μC charge due to the7 μC and 4μC charges. (b)
Use your answer to part (a) to determine the force on the 2 μC
charge

Answers

Answered by ratishkambli
1

Answer:

exerted on the 7.00−μC charge by the 2.00−μC charge is

F

1

=k

e

r

2

q

1

q

2

r

^

=

(0.500m)

2

(8.99×10

9

N.m

2

/C

2

)(7.00×10

−6

C)(2.00×10

−6

C)

×(cos60

o

i

^

+sin60

o

j

^

)

F

1

=(0.252

i

^

+0.436

j

^

)N

Similarly, the force on the 7.00μC charge by the −4.00−μC charge is

F

2

=k

e

r

2

q

1

q

3

r

^

=

(0.500m)

2

(8.99×10

9

N.m

2

/C

2

)(7.00×10

−6

C)(−4.00×10

−6

C)

×(cos60

o

i

^

−sin60

o

j

^

)

F

1

=(0.503

i

^

−0.872

j

^

)N

Thus, the total force on the 7.00−μC charge is

F

=

F

1

+

F

2

=(0.755

i

^

−0.436

j

^

)N

We can also write the total force as:

F

=(0.755N)

i

^

−(0.436N)

j

^

=

0.872Nat an angle of 330

o

solution

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