Three charges are located at the vertices of a right isosceles triangle
as shown below. What is the magnitude and direction of the resultant electric field at the midpoint M of AC?
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Explanation:
The force at A due to charge +Q at C is outward from C and the force at A due to charge -Q at B is towards B as shown in figure. So the resultant is parallel to BC. Thus there will no force in a direction normal to BC.

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