Question

Three charges are located at the vertices of a right isosceles triangle as shown below.
What is the magnitude and direction of the resultant electric field at the midpoint M of
AC?

Answer 1

Answer:

EA = electric field at M due to charge placed at A

EB = electric field at M due to charge placed at B

EC = electric field at M due to charge placed at C

from the figure

we can conclude that ,

| EB|= |EC|

net electric feild at M is ,

Enet = EA in the direction of vector 2.