Physics, asked by Erishaa, 11 months ago

Three charges each equal to 
 are placed at the corners of an equilateral triangle of side 1m. The force on one of the charges is

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Answers

Answered by Anonymous
0

Answer:

F=kq²/r²

where r = 1/(4π epsilon not)

since both the charges are equal q1q2 = q×q = q²

r is the distance between them.

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