Question

Three charges of equal magnitude are placed at corners of equilateral triangle . Force between two charges is F , the net force on each charge will be.....?

Answer 1

Explanation:

1. two repulsive forces on particle 1 adds up to to form a repulsive force

Answer 2

As all the three charges have same magnitude they will exert same force on each other. The equivalent force on a charge due to other two charges will be,

→ $F_{eq} = \sqrt{F^{2} + F^{2} + 2 F.F cos 60 }$

→ $F_{eq} = \sqrt{F^{2} + F^{2} + F^{2} }$              

     (∵cos60 = $\frac{1}{2}$ )

→ $F_{eq} = \sqrt{3F^{2}}$

→ $F_{eq} = \sqrt{3}F$

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