Three charges Q, +q and +q are placed at the vertices of an equilateral triangle of side l as shown in the figure. If the net electrostatic energy of the system is zero, then Q is equal to
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If net electrostatic energy is zero,
then net electrostatic force will also be zero
That is, F1+F2+F3 = 0
F1= kQq/l^2
F2 = kQq/l^2
F3 =kqq/l^2
So Solving this,
2Q+q = 0
Q = -q/2
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