Question

three charges Q,q1,q2 are on the vertices of a triangle. Find the value of Q when electrostatic enegy of configuration is zero?​

Answer 1

Explanation:

\blue{\bold{\underline{\underline{Answer:}}}}

Answer:

\green{\tt{\therefore{Work\:done=24\:J}}}∴Workdone=24J

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

Step−by−stepexplanation:

\begin{gathered}\green{\underline{\bold{Given :}}} \\ \tt: \implies Constant \: force(F) = 8 \: N \\ \\ \tt: \implies Displacement(s) = 3 \: m \\ \\ \red{\underline{\bold{To \: Find : }}} \\ \tt: \implies Work \: Done(W.D) = ?\end{gathered}

Given:

:⟹Constantforce(F)=8N

:⟹Displacement(s)=3m

ToFind:

:⟹WorkDone(W.D)=?

• According to given question :

\begin{gathered} \green{ \star} \tt \: \theta \: = 0 \degree \: \: \: \: (Angle \: between \: force \: and \: displacement) \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Work \: Done = FS \: cos \: \theta \\ \\ \tt: \implies Work \: Done = 8 \times 3 \times cos \:0 \degree \\ \\ \green{ \circ} \tt \: cos \: 0 \degree = 1 \\ \\ \tt: \implies Work \: Done =24 \times 1 \\ \\ \green{\tt: \implies Work \: Done =24 \: J}\end{gathered}

⋆θ=0°(Anglebetweenforceanddisplacement)

Asweknowthat

:⟹WorkDone=FScosθ

:⟹WorkDone=8×3×cos0°

∘cos0°=1

:⟹WorkDone=24×1

:⟹WorkDone=24J